Question

How many grams of oxygen gas will be produced when 2.50 moles of potassium chlorate is decomposed?

Answer 1

`m_(O_2)=120gO_2`

Step-by-step explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

`2KClO_3\rightarrow 2KCl+3O_2`

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

`m_(O_2)=2.50molKClO_3*(3molO_2)/(2molKClO_3) *(32.0gO_2)/(1molO_2)\\\\m_(O_2)=120gO_2`

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