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25 votes
Evaluate:


\bf{\sum^(32)_(n=1)\:(2n+8)

Please help A.S.A.P., thank you guys!

Please show work as well.


\bigstar

User Csaxena
by
5.8k points

1 Answer

4 votes

S₃₂ = 1312

Step-by-step explanation:


\boxed{\sf \sum _(n=1)^(32)\left(2n+8\right)}

Formula Required:


\sf sum \ of \ arithmetic \ series = (n)/(2) (2a \ + \ (n-1) \ d)

Identify the following's:

  • First Term (a) = (2(1) + 8) = 10

  • Common Difference (d) = 2nd term - first term = (2(2) + 8) - (2(1) + 8) = 2

  • Total Terms (n) = 32

Insert variables:


\rightarrow \ \sf S_(32) = (32)/(2) (2(10) + (32-1) 2) \quad \xrightarrow{\text{Simplify} } \quad 1312

User Atul O Holic
by
6.3k points
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