²-6x +10 is to be written in the form (x-p)² +g. Find the values of p and q.

asked Jun 20, 2023 230k views

2 votes

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8 votes

Answer:

$p = 3\\\\q= 1$

Explanation:

$x^2 -6x +10\\\\=x^2 -2 \cdot 3x +3^2 -3^2 +10\\\\=(x-3)^2 -9+10\\\\=(x-3)^2 +1\\\\\text{By comparing with}~ (x-p)^2 +q, \\\\p = 3\\\\q = 1$

ProxyGear answered Jun 25, 2023

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