Question

Find the range of a projectile launched at an angle of 30⁰with an initial velocity of 20m/s

Answer 1

Initial velocity of projection (u) = 20 m/s

Angle of projection (θ) = 30°

Formula of Horizontal Range of Projectile:

`\boxed{ \bf{R = (2u^2 sin\theta .cos \theta)/(g)}}`

By substituting values in the formula, we get:

`\rm \longrightarrow R = (2 * 20^2 * sin30 \degree * cos 30 \degree)/(10) \\ \\ \rm \longrightarrow R = \frac{ \cancel{2} * 40 \cancel{0} * ( √(3) )/( 2) * \frac{1}{\cancel{2}} }{ \cancel{10}} \\ \\ \rm \longrightarrow R =40 * ( √(3) )/( 2) \\ \\ \rm \longrightarrow R =20 √(3) \: m \\ \\ \rm \longrightarrow R =34.641 \: m`

`\therefore` Horizontal Range of Projectile (R) = 34.641 m