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Find the equation of circle whose centre is at (3,4) and passing through (1,5)​

User Ruka
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Answer:


(x-3)^(2) + (y-4)^(2) = r^(2) \\\\(1-3)^(2) + (5-4)^(2) = r^(2)\\r^(2) = 5 \\so the equation is \\(x-3)^(2) + (y-4)^(2) = 5

Explanation:

User Jonathan JOhx
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Answer:

Explanation:

Find the equation of circle whose centre is at (3,4) and passing through (1,5)​-example-1
User Byteunit
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