Find the equation of circle whose centre is at (3,4) and passing through (1,5)

asked Apr 23, 2021 37.2k views

3 votes

by Ruka

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2 votes

Answer:

$(x-3)^(2) + (y-4)^(2) = r^(2) \\\\(1-3)^(2) + (5-4)^(2) = r^(2)\\r^(2) = 5 \\so the equation is \\(x-3)^(2) + (y-4)^(2) = 5$

Explanation:

Jonathan JOhx answered Apr 23, 2021

4.7k points

7 votes

Answer:

Explanation:

Byteunit answered Apr 27, 2021

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