Question

Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.​

Answer 1

The range is 35.35 m

Step-by-step explanation:

Projectile Motion

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and
`g=9.8m/s^2` the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

`\displaystyle d={\frac {v_o^(2)\sin(2\theta )}{g}}`

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

`\displaystyle d={\frac {20^(2)\sin(2\cdot 30^\circ )}{9.8}}`

`\displaystyle d={\frac {400\sin(60^\circ )}{9.8}}`

`d=35.35\ m`

The range is 35.35 m