Question

Perform the indicated operation.

(4g²-9) ÷ (2g-3)

A. 2g-3

B. 2g+3

C. 2g+3 R 18​

Answer 1

Solving
`(4g^2-9) / (2g-3)` we get 2g+3

Option B is correct.

Explanation:

We need to solve
`(4g^2-9) / (2g-3)`

We know that
`a^2-b^2=(a-b)(a+b)`

So,
`4g^2-9` can be written as
`(2g)^2-(3)^2`

So, using above formula we will get:

`4g^2-9\\=(2g^2)-(3)^2 \\Using \ formula a^2-b^2 = (a-b)(a+b)\\=(2g-3)(2g+3)`

So, numerator will become

`((2g-3)(2g+3))/((2g-3)) \\Simplifying:\\=2g+3`

So, solving
`(4g^2-9) / (2g-3)` we get 2g+3

Option B is correct.