Question

Write in Java:

Given a long integer representing a 10-digit phone number, output the area code, prefix, and line number using the format (800) 555-1212.

Ex: If the input is:
8005551212

the output is:
(800) 555-1212

Hint: Use % to get the desired rightmost digits. Ex: The rightmost 2 digits of 572 is gotten by 572 % 100, which is 72.

Hint: Use / to shift right by the desired amount. Ex: Shifting 572 right by 2 digits is done by 572 / 100, which yields 5. (Recall integer division discards the fraction).

For simplicity, assume any part starts with a non-zero digit. So 0119998888 is not allowed.

LabProgram.java:

import java.util.Scanner;

public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
long phoneNumber;
// Add more variables as needed

phoneNumber = scnr.nextLong();

/* Type your code here. */
}
}

Answer 1

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

long phoneNumber;

phoneNumber = scnr.nextLong();

long areaCode = phoneNumber/10000000;

long prefix = (phoneNumber/10000)%1000;

long lineNumber = phoneNumber%10000;

System.out.println("("+areaCode+")"+prefix+"-"+lineNumber);

}

}

I hope this helps!