Solve 6x^2-2x+1=0 using any method.

asked Sep 21, 2021 161k views

2 votes

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3 votes

Answer:

$x=(1-√(-5) )/(6)\\x=(1+√(-5) )/(6)$

There are no real roots.

Explanation:

$6x^2-2x+1=0\\x=(2-√(2^2-4*6) )/(2*6) \\x=(2-√(-20) )/(12)\\x=(1-√(-5) )/(6)\\x=(1+√(-5) )/(6)$

Martin Davies answered Sep 28, 2021

4.4k points

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