Answer:

Explanation:
V(h) = h(–h + 10)(–h + 8)
Apply the distributive property to the right side and simplify.
V(h) = h(–h + 10)(–h + 8)
V(h) = {h(-h) + h(10)}(-h+8)
V(h) = (-h²+10h)(-h+8)
V(h) = (-h²)(-h) + (-h²)(8) + (10h)(-h) + (10h)(8)
V(h) = -8h² -10h² + 80h
V(h) = -18h² + 80h
Plug in the value of h from 1 to 9 (since 0<h<10) into the function V(h) = -18h² + 80h and create a table
h | V(h)
1 | 63
2 | 96
3 | 105 <------maximum volume is the highest y-value
4 | 96
5 | 75
6 | 48
7 | 21
8 | 0
9 | -9
The maximum volume for the domain 0<h<10 is 105 cubic feet.