Question

2. An object is moving with an initial velocity of 12 m/s. It accelerates at a rate of 1.5 m/s^2 over a distance of 40 m. What is its new velocity?

Answer 1

16.2 m/s

Step-by-step explanation:

2ad=Vf^2-Vi^2

2 (1.5) (40) = Vf^2 -(12)^2

Vf= 16.2 m/s