Question

Calculate the molarity of a sodium hydroxide solution if 50.0 mL of this solution was completely neutralized by 46.6 mL of 0.750 M sulfuric acid.

Answer 1

Answer: 0.699 M

Step-by-step explanation:

`M_(A)V_(A)=M_(B)V_(B)\\(0.750)(46.6)=M_(B)(50.0)\\M_(B)=(0.750)(46.6))/(50.0)=\boxed{0.699 \text{ M}}`