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Model With Mathematics During a football game, a kicker is called in twice to kick a field goal from the 30 yard line. Suppose that for each attempt, the probability that he will make the field goal is 0.8.

a. What is the probability that he will make both field goals?

b. What is the probability that he will make neither field goal?​

User Ssemichev
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2 Answers

3 votes

Final answer:

The probability that the kicker will make both field goals is 0.64. The probability that the kicker will make neither field goal is 0.36.

Step-by-step explanation:

To find the probability that the kicker will make both field goals, we can multiply the individual probabilities. Since the probability of making each field goal is 0.8, the probability of making both field goals is 0.8 * 0.8 = 0.64.

To find the probability that the kicker will make neither field goal, we can subtract the probability of making both field goals from 1. So, 1 - 0.64 = 0.36.

User Fancyoung
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1 vote

Answers:

  • (a) 0.64
  • (b) 0.04

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Step-by-step explanation:

Assuming each kick is independent of any other, this means the probability of making two field goals in a row is 0.8*0.8 = 0.64

The probability of missing any single field goal is 1-0.8 = 0.2; so the probability of missing two in a row is 0.2*0.2 = 0.04

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Extra info:

Adding up those results shows that 0.64+0.04 = 0.68 is the probability of either making 2 in a row or missing 2 in a row; that leaves 1-0.68 = 0.32 to represent the probability of making exactly one field goal in either order.

Or you could note that 0.8*0.2+0.2*0.8 = 0.32

User Dave Rottino
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