Which equation is the inverse of y=16x^2+1

Question

asked Jul 21, 2021 97.9k views

1 Answer

Kjagiello · Answer 1 · 2021-07-25T16:34:38+0000

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$y = 16 {x}^(2) + 1$

Subtract sides 1

$y - 1 = 16 {x}^(2) + 1 - 1$

$y - 1 = 16 {x}^(2)$

$16 {x}^(2) = y - 1$

Divide sides by 16

$\frac{16 {x}^(2) }{16} = (y - 1)/(16) \\$

${x}^(2) = (y - 1)/(16) \\$

$x = ± \sqrt{ (y - 1)/(16) } \\$

$x = ± \: (1)/(4) √(y - 1) \\$

Thus ;

${f}^( - 1) (x) = ± \: (1)/(4) √(y - 1) \\$

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