Question

The pressure inside a sealed container of methane gas (CH4) is 35.0 kPa. If this 80.0 L sample

of methane is increased to a pressure of 92.0 kPa, what is the new volume?

Answer 1

The answer is 30.43 L

Step-by-step explanation:

The new volume can be found by using the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

Since we are finding the new volume

`V_2 = (P_1V_1)/(P_2) \\`

From the question we have

`V_2 = (35000 * 80)/(92000) = (2800000)/(92000) = (700)/(23) \\ = 30.434782...`

We have the final answer as

30.43 L

Hope this helps you