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Pls Help! John wants to prove ABC = to DEF. He Knoes AB = DE and AC = DF. With Screenshot

Pls Help! John wants to prove ABC = to DEF. He Knoes AB = DE and AC = DF. With Screenshot-example-1
User RubberDuck
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1 Answer

3 votes

Answer:


\angle A \cong \angle D

Explanation:

The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.

Thus, since John already knows that
\overline{AB} \cong \overline{DE} and
\overline{AC} \cong \overline{DF}, therefore, an additional information showing that the angle between
\overline{AB} and
\overline{DE} in ∆ABC is congruent to the angle between
\overline{AC} and
\overline{DF} in ∆DEF.

For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be
\angle A \cong \angle D.

See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.

Pls Help! John wants to prove ABC = to DEF. He Knoes AB = DE and AC = DF. With Screenshot-example-1
User Talib Daryabi
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5.7k points