Question

What is the density of a bar of lead that weighs 173 g and has the following dimensions: l= 2.00 cm, w = 3.00 cm, h = 1.00 in?

Answer 1

`\rho=7373.2g/cm^3`

Step-by-step explanation:

Hello!

In this case, since the density is defined as the degree of compactness of a substance, and is defined as the mass over the volume:

`\rho= (m)/(V)`

Given the dimensions of the bar of lead, we can compute the volume as shown below:

`V=2.00cm*3.00cm*1.00in*(1in)/(2.54cm) \\\\V=2.36cm^3`

Thus, the density turns out:

`\rho=(173g)/(2.36cm^3) \\\\\rho=7373.2g/cm^3`

Best regards!