Question

An irregular shaped piece of metal wha a mass of 0.251 lb was placed into a graduated cylinder containing 50.00 mL of water; this raised the water to 67.50 mL.

What is the density, in g/cm3, of the metal?

Answer 1

`\rho= 6.51g/cm^3`

Step-by-step explanation:

Hello!

In this case, since the density is defined as the degree of compactness of a substance, and is defined as the mass over the volume:

`\rho= (m)/(V)`

Given the displaced volume, we can compute the volume of the piece of metal via the following subtraction:

`V=67.50mL-50.00mL=17.50mL=17.50cm^3`

Since the piece of metal displaces the water to the final volume. Moreover, given the mass in lb, we compute it grams as follows:

`m=0.251lb*(453.6g)/(1lb) =113.85g`

Thus, the density turns out:

`\rho= (113.85g)/(17.50cm3)\\\\\rho= 6.51g/cm^3`

Best regards.