25.9k views
4 votes
Jamie had seven posters, but only three could fit on his closet door. How many different ways can he arrange the three posters out of the seven on his closet door?

A. 52.5
B. 210
C. 1260
D. 5,040

2 Answers

8 votes

Answer:

B. 210 is correct!

Step-by-step explanation:

I got it correct on the quiz.

Jamie had seven posters, but only three could fit on his closet door. How many different-example-1
User Johan Prinsloo
by
4.1k points
8 votes

Answer: 210

Step-by-step explanation:

Jamie has 7 choices for the first slot, then 6 choices for the next, and 5 choices for the final slot. Order matters. He has 7*6*5 = 210 permutations.

Alternatively you can use the nPr permutation formula with n = 7 and r = 3.

That formula is


nPr = (n!)/((n-r)!)

The exclamation marks indicate factorials. For instance, 4! = 4*3*2*1 = 24.

User Cano
by
4.1k points