Question

if a ball is released from a height 80cm how long would it take the ball to reach the ground when g= 10m per seconds​

Answer 1

Hope you could understand.

If you have any query, feel free to ask.

Answer 2

The ball took 0.4 seconds

Step-by-step explanation:

» From the second newton's equation of motion.

`{ \boxed{ \tt{s = ut + (1)/(2) {gt}^(2) }}}`

• s is displacement, s = 80cm, s = 0.8 meters
• u is initial velocity, u = 0 [ from rest ]
• g is 10 m/s²

`{ \tt{0.8 = (0 * t) + ( (1)/(2) * 10 * {t}^(2) )}} \\ \\ { \tt{0.8 = 5 {t}^(2) }} \\ { \tt{ {t}^(2) = 0.16 }} \\ { \tt{t = √(0.16) }} \\ \\ { \underline{ \underline{ \tt{ \: time = 0.4 \: seconds \: \: }}}}`