Answer:
20,000 bricks
Explanation:
length of brick(L)=22cm
breadth of brick(B)=15cm
now,
area of brick(A)=L×B
=22×15s.q.cm
=0.033s.q.m
again,
length of court(l)=30m
breadth of court(b)=22m
now,
area of court(a)=l×b
=30×22s.q.m
=660s.q.m
lastly,
no.of required brick=area of court/area of
brick
=600 s.q.m/0.033s.q.m
=20,000bricks