If 33.9 ml of h3po4 neutralizes 23.4 ml of 2.28 m koh, what is the molarity of the phosphoric acid?

asked Jul 25, 2023 142k views

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4 votes

Answer: 1.57 M

Step-by-step explanation:

$M_(A)V_(A)=M_(B)V_(B)\\(33.9)M_(A)-=(23.4)(2.28)\\M_(A)=((23.4)(2.28))/(33.9)=\boxed{1.57 \text{ M}}$

AidanCurran answered Jul 30, 2023