Question

Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is selected. Find the probability of selecting a six and then selecting a five.

Answer 1

`(16)/(2704)`

Explanation:

In a standard deck of 52 playing cards, there are 4 variations of every number. These would be 1 of Spade , 1 of Heart , 1 of Clubs , and 1 of Diamonds. Therefore the possibility of getting one of these numbers is 4/52. In order to find the probability of selecting a six and then selecting a five in consecutive order, we need to multiply the probability of selecting the six by the probability of selecting a five.

`(4)/(52) * (4)/(52) =`
`(16)/(2704)`

Therefore, the probability of this happening would be
`(16)/(2704)`