Question

A hamburger containing 335.4 kcal of energy was combusted in a bomb calorimeter with an unknown heat capacity. The temperature of the water bath increased by 18.2 K. What's Cv for this calorimeter

Answer 1

`Cv_(calorimeter)=18.4kcal/K`

Step-by-step explanation:

Hello!

In this case, since the combustion of the hamburger released 335.4 kcal of energy and that energy is received by the calorimeter, we can write:

`Q_(hamburguer)=-Q_(calorimeter)`

And the heat of the calorimeter is written in terms of the temperature change and the calorimeter constant:

`Q_(hamburguer)=-Cv_(calorimeter)\Delta T`

Thus, given the released heat by the hamburger due to its combustion and the temperature change, Cv for the calorimeter turns out:

`Cv_(calorimeter)=(-Q_(hamburguer))/(\Delta T) =(-(-335.4kcal))/(18.2K)\\\\Cv_(calorimeter)=18.4kcal/K`

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