We are given:
Sinθ - √3 Cosθ = 1
Solving for θ:
dividing both the sides by 2
1/2 Sinθ - √3/2 Cosθ = 1/2
Cos(60°)*Sinθ - Sin(60°)Cosθ = Sin(30°) [Since Cos(60°) = 1/2 and Sin(60°)=√3/2]
We can see that the LHS resembles the formula:
Sin(A - B) = SinACosB - SinBCosA
Sin(θ - 60°) = Sin(30°)
So, we can say that:
θ - 60 = 30
θ = 90° or π/4 radians