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Lugi is trying to hit a turtle shell. The height of

Lugi's feet above the ground is given by the
functionh(t) = -16t² +961 + 2.
How long does it take for Lugi to hit the shell on the ground?
A. 3 seconds
B. 146 seconds
0.6.02 seconds
D. 16 seconds

Lugi is trying to hit a turtle shell. The height of Lugi's feet above the ground is-example-1

1 Answer

1 vote

Answer:

C. 6.02sec

Explanation:

Given


h(t) = -16t\² +96t + 2

Required

Time to hit the ground

When the turtle shell hits the ground,
h(t) = 0

So:


0 = -16t\² +96t + 2.

Solving using quadratic formula:


t = (-b\±√(b^2-fac))/(2a)

Where:


a = -16; b =96; c = 2

So:


t = (-96\±√(96^2-4 * -16 * 2))/(2*-16)


t = (-96\±√(9344))/(-32)


t = (-96\±96.66)/(-32)

Split:


t = (-96+96.66)/(-32) or
t = (-96-96.66)/(-32)


t = (0.66)/(-32) or
t = (-192.66)/(-32)


t = -0.020625 or
t = 6.020625

So time can't be negative, we have:


t = 6.020625

Option C answers the question

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