Question

how would you find the displacement from t = 0.3 to t = 0.33 under this graph? would it be measured on the time axis?

Answer 1

Step-by-step explanation:

from t = .3 to t = .33 , velocity appears to be uniform .

uniform velocity = .22 m /s

displacement will be area of the v-t graph which is a rectangle .

= .22 x ( .33 - .3 )

= .22 x .03

= 66 x 10⁻⁴ m

= 6.6 mm .