Question

Can anyone help with this?

Answer 1

The concentration of the acid solution : 0.43 M

Further explanation

Reaction

Cu + 2HCl ⇒ CuCl₂ + H₂

• the amount of Cu reacting :

`\tt 13.36-4.54=8.82~g`

• mol Cu :(Ar=63.5 g/mol))

`\tt (8.82)/(63.5)=0.139`

• concentration of the acid solution(HCl) :

mol HCl :

`\tt (2)/(1)* 0.139=0.278`

concentration :

`\tt M=(mol)/(V)=(0.278)/(0.65~L)=0.43`