Explanation:
n! = n × n−2 × n−3 × ... × 2 × 1
(n+1)! = n+1 × n × n−2 × n−3 × ... × 2 × 1
(n+1)! = (n+1) n!
Therefore:
lim(n→∞) (n! / (n+1)!)
lim(n→∞) (n! / ((n+1) n!))
lim(n→∞) (1 / (n+1))
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Answer:
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