Question

a serving of cheese its releases 130kcal when digested. if this energy was transferred to 2.5kg of water at 27 degrees celsius, what would the final temperature be?

Answer 1

The final temperature : 79.07°C

Further explanation

Heat transferred can be formulated

Q=m.c.ΔT

Q= heat, J

m=mass,g

c=specific heat, for water 4.18 J/g C

ΔT = temperature

Heat transferred : 130 kcal

1 kcal = 4186 J

130 kcal =

`\tt 130* 4186=544180~J`

mass = 2.5 kg =2500 g

t₁=27 °c

The final temperature :

`\tt 544180=2500* 4.18* (t_2-27)\\\\t_2-27=52.07\\\\t_2=79.07^oC`