Question

2log(base 5)^(x-3)-log(base 5)^8= log(base 5)^2

Answer 1

x = 7

Explanation:

`2log_5(x-3)-log_58= log_52\\\\</p><p>2log_5(x-3) =log_52+log_58\\\\</p><p>2log_5(x-3) =log_5(2* 8) \\\\</p><p>2log_5(x-3) =log_516\\\\</p><p>2log_5(x-3) =log_54^2 \\\\</p><p>2log_5(x-3) =2 log_54 \\\\</p><p>log_5(x-3) =log_54 \\\\</p><p>x - 3 = 4\\\\</p><p>x = 4+3\\\\</p><p>\huge \orange { \boxed{x = 7}}</p><p>`