Question

a water line starts the service with an altitude of 1200m over the sea level, what is the velocity of the water above 1050 m over the sea level?

Answer 1

Velocity = 94.85m/s

Step-by-step explanation:

Given the following data ;

Height = 1200m

Vertical distance = 1050m

To find the time, we would use the second equation of motion;

`S = ut + \frac {1}{2}at^(2)`

Substituting into the equation, we have;

`1200 = 0(t) + \frac {1}{2}*9.8*t^(2)`

`1200 = 0 + 4.9*t^(2)`

`1200 = 4.9*t^(2)`

`t^(2) = \frac {1200}{4.9}`

`t = √(122.45)`

t = 11.07 secs

To find the velocity;

Mathematically, velocity is given by the equation;

`Velocity = (distance)/(time)`

Substituting into the above equation;

`Velocity = (1050)/(11.07)`

Velocity = 94.85m/s

Therefore, the velocity of the water above 1050 m over the sea level is 94.85m/s.