Question

Plzzzzz helpppppp!!! ( Write an equation of the line in slope-intercept form)

Answer 1

3). y = 2x - 2

4). y = (4/3)x - 1

Explanation:

3).

First find the slope

(y2 - y1) / (x2 - x1) or rise/run

(0 - (-2)) / (1 - 0) = 2

2 is your slope

Now use the equation below for using coordinates for finding slope intercept form.

y - y1 = m(x - x1)

y1 = y number of given coordinate

x1 = x number of given coordinate

m = slope

y - 0 = 2(x - 1)

Distribute

y - 0 = 2x + (-2)

Get y by itself by adding 0 to both sides.

y - 0 = 2x + (-2)

+0 +0

y = 2x - 2

4).

Repeat the same process for 4 as done in 3

Find the slope

(y2 - y1) / (x2 - x1) or rise/run

(3 - (-1)) / (3 - 0) = 4/3

4/3 is your slope

Now use the equation below for using coordinates for finding slope intercept form.

y - y1 = m(x - x1)

y1 = y number of given coordinate

x1 = x number of given coordinate

m = slope

y - 3 = (4/3)(x - 3)

Distribute

y - 3 = (4/3)x + (-4)

Get y by itself by adding 3 to both sides.

y - 3 = (4/3)x + (-4)

+3 +3

y = (4/3)x - 1

Answer 2

3. y = 2x - 2

4. y =
`(4)/(3)x-1`

Explanation:

3. Slope = 2

Y-intercept = -2

4. Slope =
`(4)/(3)`

Y-intercept = -1