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How many solutions does 9x^2+ 6x + 1 = 0 have?

(a) one real and one nonreal complex solution
(b) two distinct real solutions
(c) one real solution with multiplicity 2
(d) two nonreal complex solutions
(e) one nonreal complex solution with multiplicity 2

2 Answers

5 votes

Answer:

(c). one real solution

Explanation:

9x² + 6x + 1 = 0

D = 6² - 4(9)(1) = 0 ⇒ one real solution with multiplicity 2

User Mabalenk
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7.4k points
1 vote
Answer: I am pretty sure it is c
Solving Steps:
How many solutions does 9x^2+ 6x + 1 = 0 have? (a) one real and one nonreal complex-example-1
User Changnam Hong
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7.7k points