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What is the force of friction between a block of ice (weighs 930N) and the ground if µs = .12?

1 Answer

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Answer: 111.6

Explanation: You would multiply the normal force of the block of ice which is the same number as the weight that was given (930N) , you multiply that by .12 to get the answer of 111.6 N as the force of friction.

User Wellington Lorindo
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