Answer:
The climber moves 15 feet per hour.
Explanation:
A rock climber's height, in feet, when climbing a shear wall can be expressed by the equation h=15t, where t is time measured in hours
h is distance and t is time.
![(h)/(t)=15](https://img.qammunity.org/2021/formulas/mathematics/college/ten8nlbc8tln1f2hyoindk6e70too78ozu.png)
or
![(d)/(t)=15](https://img.qammunity.org/2021/formulas/mathematics/college/tednkqv16o8h97jtmxo6oe7qqiso1qkbpu.png)
Distance per unit time is equal to the velocity of an object.
velocity = 15 feet per socond
Hence, the climber moves 15 feet per hour.