Question

Can someone show their work on how to do this: Calculate the number of moles of Al2O3 present in 23.87g. (Molar mass of Al2O3= 102.0g/mol)

Answer 1

0.234 moles

Step-by-step explanation:

moles of Al2O3 = mass / molar mass

moles of Al2O3 = 23.87g / 102.0g/mol

moles of Al2O3 = 0.234 moles (to three significant figures)