Question

What are the zeros of the quadratic function f(x) = 6x² - 24x + 1?

A.

`x = - 2 + \sqrt{ (1)/(2) } or \: x = - 2 \: - \sqrt{ (1)/(2) }`
B.

`x = 2 + \sqrt{ (1)/(2) } \: or \: x = 2 - \sqrt{ (1)/(2) }`
C.

`x = - 2 + \sqrt{ (23)/(6) } \: or \: x = - 2 - \sqrt{ (23)/(6) }`
D.

`x = 2 + \sqrt{ (23)/(6) } \: or \: x = 2 - \sqrt{ (23)/(6) }`
​

Answer 1

D.

Explanation:

Use Quadratic formula

x = [-b +- sqrt (b^2 - 4ac) ] / 2a with a = 6 b = -24 c = 1

to find

x = 2 ± sqrt (23/6)