Question

What is an equation of the line that passes through the point (-1, -3) and is perpendicular to the line y=1/2x-7 ?

Please help

Answer 1

y = -2x - 5

Explanation:

Set the slope of the given equation to the reciprocal to get a perpendicular slope:

y = 1/2x --> -2x

y = -2x + b will be your current equation. To get b, you must insert the given information: (-1, -3)

-3 = -2 (-1) + b

Solve:

-3 = 2 + b

-2 -2

-5 = b

Thus your equation would be y = -2x - 5.