Answer:
11
Explanation
We first let the side of the square be defined as x.
Therefore, we have ax/2 = 4, and bx/2= 3. Where a and b are the legs of the triangles with areas 4 and 3 respectively.
For the Triangle with area 6, we then have ((x-a)(x-b))/2 = 6. Expanding gives us x^2-bx-ax+ab=12. Using the equation above and plugging in values where bx = 6, ax=8, a = 8/x, and b = 6/x. We get
x^2-6-8+48/x^2 = 12.
Simplified gives us,
x^4-26x^2+48.
Factored gives us,
((x^2-2)(x^2-24).
Since the area cannot be any negative values and bigger than 6 (since there is already a triangle with area 6), we then have x^2 = 24.
Therefore a of unshaded region = 24-6-4-3= 11