Question

Two dice are rolled. Event A is that the sum of the numbers is 7 or 11. Event B is that the sum of the numbers is 11 or 12. Find the probability of Event A or B, i.e., find P (A union B).

I got 9/36

Answer 1

9/36 = 1/4

Step-by-step explanation:

sums:

7 = 6 combinations

11= 2 combinations

12= 1 combination

Event A 7 or 11

Event B 11 or 12

P(A∪B) = 9/36

Hope this helps

Answer 2

There are 36 total possible ways the dice may fall.

Ways to get a 7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1 : 6 ways.

Ways to get an 11: 5+6, 6+5 : 2 ways.

So there are 8 ways the sum can be 7 or 11 out of the 36 total possibilities. Probability: 8/36=2/9.