Question

) A rectangles length is 4 more than 3 times its width.

Its perimeter is 152. Find the length and width.

Answer 1

no entiendo nada

Explanation:

Answer 2

Let the width of the rectangle be 'w'

According to the question length of the rectangle (l) is 4 more than 3 times it's width;

`\longrightarrow` l = 3w + 4

Perimeter of rectangle = 152

Formula of perimeter of rectangle = 2(Length + Width)

So,

`\rm \implies 2(Length + Width) = 152 \\ \\ \rm \implies 2(3w + 4+ w) = 152 \\ \\ \rm \implies 2(4w + 4) = 152 \\ \\ \rm \implies 2 * 4(w + 1) = 152 \\ \\ \rm \implies 8(w + 1) = 152 \\ \\ \rm \implies w + 1 = (152)/(8) \\ \\ \rm \implies w + 1 = 19 \\ \\ \rm \implies w = 19 - 1 \\ \\ \rm \implies w = 18`

`\therefore` Width of the rectangle (w) = 18

Length of rectangle (l) = 3 × 18 + 4 = 58