Question

What is the equation of the line that has a slope of -6/5 and goes through the point (5, -4)?

Answer 1

Explanation:

Given

slope =6/5

point =(5, -4)

So

the equation of the line =

(y-y1)=m(x-x1)

Where X1=5,y1=-4,m=6/5

Put the values

(Y+4)=6/5(x-5)

5(Y+4)=6(x-5)

5y+20=6x-30

5y-6x=-30-20

-6x+5y=-50

6x-5y=50.

So the equation of the line is 6x-5y=50.