Question

HELP FAST 10 POINTS

what is the equation of a line that is perpendicular to the line that goes through the points (0,-3) and (-3,12)
A:Y=15x+2
B:Y=-1/15x-8
c:y=-9x-7
D:y=1/5x-3

Answer 1

y=1/5x-3

Explanation:

Start by finding the slope:

Slope = (y₂-y₁)/(x₂-x₁)

Now we plug in the coordinates:

Slope = (12-(-3))/(-3-0)=(12+3)/(-3)=15/-3=-5

The slope intercept equation would be

y=mx+b

Slope is m and y-intercept is b. x and y and the x and y-coordinates.

Now we plug in one of the x and y coordinate pairs into the equation:

-3=-5(0)+b

b=-3

So the equation of the line would be

y=-5x-3

But the slope of a perpendicular line is the negative reciprocal of the original equation

So...

y=1/5x-3