Question

A rectangle has a length of (x+10) centimeters and a width of x centimeters. If the perimeter is 32 centimeters, what is the length of the rectangle?

Answer 1

Given:

Length of rectangle = (x+10) cm

Width of the rectangle = x cm

Perimeter = 32 cm

To find:

The length of the rectangle.

Solution:

We know that,

`Perimeter=2(l+w)`

Where, l is length and w is width.

Substituting the values, we get

`32=2((x+10)+x)`

`32=2(2x+10)`

`32=4x+20`

Subtract 20 from both sides.

`32-20=4x`

`12=4x`

Divide both sides by

`3=x`

So, the length is

`3+10=13`

Therefore, the length of the rectangle is 13 cm.