Question

Write the net ionic equation for the reaction that occurs when equal volumes of 0.080 M aqueous acetic acid and sodium nitrite are mixed. It is not necessary to include states such as (aq) or (s).

Answer 1

CH₃COO⁻ + NaNO₂ → CH₃COONa + NO₂⁻

Step-by-step explanation:

When equal volumes of 0.080 M aqueous acetic acid and sodium nitrite are mixed (1:1), we have:

Acetic acid = CH₃COOH

Sodium nitrite = NaNO₂

The molecular equation is:

CH₃COOH(aq) + NaNO₂(s) → CH₃COONa(s) + HNO₂(aq)

The ionic equation is:

CH₃COO⁻H⁺ + Na⁺NO₂⁻ → CH₃COO⁻Na⁺ + H⁺NO₂⁻

The net ionic equation is:

CH₃COO⁻ + NaNO₂ → CH₃COONa + NO₂⁻

I hope it helps you!