Answer:
43.2%
Step-by-step explanation:
Given that,
Heat absorbed by a carnot heat engine,
![Q_1=235\ kW](https://img.qammunity.org/2021/formulas/engineering/college/wikrq7bu3zfkal3ngentz9xyic9tgzmnnc.png)
Heat rejected to the atmosphere,
![Q_2=164\ kW](https://img.qammunity.org/2021/formulas/engineering/college/8m5s9an13cyst0f2yqqbvz4mxggen7eatw.png)
We need ti find the thermal efficiency of the heat engine. It is equal to the ratio of output work to the energy supplied. Its mathematical form is given by :
![\eta=1-(Q_1)/(Q_2)\\\\\eta=1-(235)/(164)\\\\\eta=-0.432](https://img.qammunity.org/2021/formulas/engineering/college/8m68howkbtyhsfiyl831gxa8a1ctyohu2u.png)
or
![\eta=-43.2\%](https://img.qammunity.org/2021/formulas/engineering/college/qi3tru8dj36q8eovbhntnzp3lj64bfaqfn.png)
The egative value of efficiency shows work is done by the engine.