Answer:
28.04g of NaClO2 must be dissolved
Step-by-step explanation:
When NaClO2 and HClO2 are mixed in a solution, a buffer is produced. The pH of this buffer is obtained using H-H equation:
pH = pKa + log [NaClO2] / [HClO2]
Where pKa is -log Ka = 1.9586
And [NaClO2] and [HClO2] could be taken as moles of each compound.
Moles of HClO2 are:
250mL = 0.250L * (1.60mol / L) = 0.40 moles HClO2.
Replacing:
pH = pKa + log [NaClO2] / [HClO2]
1.45 = 1.9586 + log [NaClO2] / [0.40mol]
0.31mol = [NaClO2]
To convert these moles to mass we need to use molar mass of NaClO2: 90.44g/mol:
0.31mol * (90.44g / mol) =
28.04g of NaClO2 must be dissolved