The solubility of gas in water at 25 C and 1.0 atm pressure of oxygen is 0.061 g/ L. What would the pressure be if the solubility of oxygen water at 25 C is 0.075 g/L

Question

asked Apr 16, 2021 22.0k views

1 Answer

Mike Thompson · Answer 1 · 2021-04-19T23:23:01+0000

Answer:

P2 = 1.2265 atm (Approx)

Step-by-step explanation:

Given:

Water temperature = 25 degree Celsius

Pressure = 1 atm

So,

P1/P2 = C1/C2

1 / P2 = 0.061 / 0.075

P2 = 1.2265 atm (Approx)