Question

Consider an instruction within a certain instruction-set architecture (ISA): ADD R1, R2, R3. This instruction adds the value in Register R1 with the value in Register R2, and stores the result in Register R3. What is the maximum number of physical memory accesses that may be caused by this single instruction?

a) 1
b) 2
c) 3
d) 4

Answer 1

C = 3

Step-by-step explanation:

The maximum number of physical memory accesses that may be caused by this single instruction is ; 3

This is because In the case of loading two values into R2 and R3 there is need for their memories to be accessed and after execution R1 value there will be a write back into memory hence another memory is also accessed and that makes the number of Physical memories accessed to be three(3) in Total